Bei einer Funktion 3. Grades sind es 4 Bedingungen und ich konnte nur 3 herauslesen. Deshalb habe ich einen kurzen Blick in die Lösung geworfen und herausgefunden das die Angabe ”berührt die x-Achse im Ursprung” zwei Bedingungen enthält. Das wären einmal f(0)=0 und f'(0)=0 , ich wollte fragen ob mir jemand erkären kann, wie die Bedingung f'(0)=0 zustande kommt. Bin echt ziemlich planlos. Eine ganz rationale Funktion 3.Grades ist punktszmmetrisch zum Ursprung.
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